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array reduce javascript

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Javasper answered on May 21, 2020 Popularity 10/10 Helpfulness 1/10

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const numbers = [260, 25, 35];

console.log(numbers.reduce(myFunc))

function myFunc(total, num) {
  return total - num;
}
/*console.log will show 200 since the first element minus 35 and minus 25 is 260-25-35=200*/
/*while the name is "reduce", you do NOT have to subtract. Reduce() is more about "take the first element as total, and do something(whatever the function says) to it for each of the remaining elements; the remaining elements will be identified as the second parameter num for the function myFunc, you do whatever once for all remaining elements*/

Popularity 10/10 Helpfulness 1/10 Language javascript

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Contributed on Jul 31 2022

Javasper

0 Answers Avg Quality 2/10

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javascript reduce

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177

var array = [36, 25, 6, 15];

array.reduce(function(accumulator, currentValue) {
  return accumulator + currentValue;
}, 0); // 36 + 25 + 6 + 15 = 82

Popularity 10/10 Helpfulness 4/10 Language javascript

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Tags: javascript j

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Contributed on May 21 2020

TC5550

0 Answers Avg Quality 2/10

JavaScript Reduce

Comment

const arr = [1, 2, 3]
const result = arr.reduce((acc, curr) => acc + curr, 0)
// 1 + 2 + 3 = 6
console.log(result)

Popularity 10/10 Helpfulness 4/10 Language javascript

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Tags: javascript j

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Contributed on Dec 21 2022

Jozvan

0 Answers Avg Quality 2/10

js reduce

Comment

// syntax: array.reduce(function, accumulator-initial-value)
let array = [3, 7, 2, 9, 5]
const result = array.reduce((accumulator, currentValue, currentIndex, arr) => {
  // code
}, initialValue)

// accumulator = will store return value of the function
// currentValue = iterate through each array element
// currentIndex = index of currentValue
// arr = original array
// initialValue = set accumulator initial value

Popularity 10/10 Helpfulness 4/10 Language javascript

Source: developer.mozilla.org

Tags: javascript j

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Contributed on Jul 21 2021

Suman Majhi

0 Answers Avg Quality 2/10

reduce javascript

Comment

let array = [36, 25, 6, 15];
 
array.reduce((acc, curr) => acc + curr, 0)
// 36 + 25 + 6 + 15 = 82

Popularity 10/10 Helpfulness 4/10 Language javascript

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Tags: javascript j

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Contributed on Jul 05 2022

Rick Oburu

0 Answers Avg Quality 2/10

reduce javascript

Comment

var depthArray = [1, 2, [3, 4], 5, 6, [7, 8, 9]];

depthArray.reduce(function(flatOutput, depthItem) {
    return flatOutput.concat(depthItem);
}, []);

=> [1, 2, 3, 4, 5, 6, 7, 8, 9];


// --------------
const prices = [100, 200, 300, 400, 500];
const total = prices.reduce((total, cur) => {return total + cur} )
//  init value = 0 => total = 1500;


// --------------
const prices = [100, 200, 300, 400, 500];
const total = prices.reduce(function (total, cur) => {
                   return total + cur
                }, 1 )
// init value = 1 => so when plus all numnber will be result => 1501;

// --------------
const prices = [100, 200, 300, 400, 500];
const total = prices.reduce((total, cur) => total + cur )
// 1500;

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Contributed on Mar 03 2022

Zidane (Vi Ly - VietNam)

0 Answers Avg Quality 2/10

js reduce

Comment

Sum array elements:
let myArr = [1,2,3,-1,-34,0]
return myArr.reduce((a,b) => a + b,0)

Popularity 10/10 Helpfulness 3/10 Language javascript

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Contributed on Dec 27 2020

Encouraging Earthworm

0 Answers Avg Quality 2/10

javascript reduce

Comment

const sum = array.reduce((accumulator, element) => {
  return accumulator + element;
}, 0);

Popularity 10/10 Helpfulness 3/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Apr 11 2021

Cooperative Capybara

0 Answers Avg Quality 2/10

js array reduce

Comment

// Arrow function
reduce((previousValue, currentValue) => { /* ... */ } )
reduce((previousValue, currentValue, currentIndex) => { /* ... */ } )
reduce((previousValue, currentValue, currentIndex, array) => { /* ... */ } )
reduce((previousValue, currentValue, currentIndex, array) => { /* ... */ }, initialValue)

// Callback function
reduce(callbackFn)
reduce(callbackFn, initialValue)

// Inline callback function
reduce(function(previousValue, currentValue) { /* ... */ })
reduce(function(previousValue, currentValue, currentIndex) { /* ... */ })
reduce(function(previousValue, currentValue, currentIndex, array) { /* ... */ })
reduce(function(previousValue, currentValue, currentIndex, array) { /* ... */ }, initialValue)

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Source: developer.mozilla.org

Tags: array-reduce array-redu

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Contributed on Feb 21 2022

Tung

0 Answers Avg Quality 2/10

array reduce

Comment

const values = [4, 3, 2, 1];
console.log("Before reduce");
const sum = values.reduce((accumulator, current) => {
  const result = accumulator + current;
  console.log(
    `accumulator: ${accumulator}, current: ${current}, result: ${result}`
  );
  //accumulator will be used to store the result and will be used in the next iteration
  return result;
});
console.log("After reduce");

// Before reduce
// accumulator: 4, current: 3, result: 7
// accumulator: 7, current: 2, result: 9
// accumulator: 9, current: 1, result: 10
// After reduce

console.log(sum); // => 10

Popularity 9/10 Helpfulness 3/10 Language javascript

Source: koenwoortman.com

Tags: array-reduce array-redu

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Contributed on Jul 17 2023

Bongui

0 Answers Avg Quality 2/10

javascript reduce

Comment

[3, 2.1, 5, 8].reduce((total, number) => total + number, 0)

// loop 1: 0 + 3
// loop 2: 3 + 2.1
// loop 3: 5.1 + 5
// loop 4: 10.1 + 8
// returns 18.1

Popularity 10/10 Helpfulness 3/10 Language typescript

Source: dev.to

Tags: javascript j

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Contributed on Aug 10 2021

Troubled Tiger

0 Answers Avg Quality 2/10

array reduce javascript

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